Tayarri SAT
Math, Advanced Math, Stage 2

Quadratics on the SAT: lesson and practice

SAT quadratic questions test four things: solving (factor, take square roots, or use the quadratic formula), the vertex (the minimum or maximum point, at x = −b/(2a)), the sum and product of solutions (−b/a and c/a), and the number of solutions (from the discriminant b² − 4ac).

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Solving

FormBest methodExample
x² + bx + c = 0Factorx² − 5x − 14 = (x − 7)(x + 2) → 7, −2
(x − h)² = kSquare root, both signs(x − 3)² = 16 → x = 7 or −1
Anything elseQuadratic formula or Desmosx = (−b ± √(b² − 4ac)) / 2a

The vertex

In y = a(x − h)² + k, the vertex is (h, k). In y = ax² + bx + c, it is at x = −b/(2a); substitute to get the minimum or maximum value.

Two shortcuts

Asked forFormula
Sum of solutions−b/a
Product of solutionsc/a
Number of real solutionsb² − 4ac: positive → 2, zero → 1, negative → 0

Common mistakes

Wrong signs from factors(x − 7) gives x = 7, not −7.
Only the positive square root(x − 3)² = 16 has two solutions.
Squaring a negative(−3)² = 9.
Giving the x-value instead of the minimum valueThe minimum value is the y-value of the vertex.

Sample questions with answers

1. What are the solutions to x² − 5x − 14 = 0?
  1. x = −7 and x = 2
  2. x = 7 and x = −2 (correct)
  3. x = 14 and x = −1
  4. x = 5 and x = −14

(x − 7)(x + 2) = 0, so x = 7 or x = −2.

2. What is the vertex of y = 2(x + 3)² − 5?
  1. (3, −5)
  2. (−3, −5) (correct)
  3. (−3, 5)
  4. (−5, −3)

x + 3 = x − (−3), so h = −3 and k = −5.

3. How many real solutions does x² + 4x + 5 = 0 have?
  1. Zero (correct)
  2. Exactly one
  3. Exactly two
  4. Infinitely many

16 − 20 = −4 is negative, so there are no real solutions.

Frequently asked questions

How many quadratic questions are on the SAT?

Quadratics are a major part of Advanced Math, which makes up about 35% of SAT Math, roughly 13 to 15 questions.

Do I need to memorize the quadratic formula for the SAT?

It helps, but many SAT quadratics can be factored or solved with Desmos. Know the formula as a backup.

How do I find the minimum value of a quadratic?

Find the vertex x-value with −b/(2a), then substitute it into the function. The result is the minimum (if a > 0).

What is the discriminant used for?

b² − 4ac tells you how many real solutions a quadratic has: positive means two, zero means one, negative means none.

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